Stewart Manaog vs Truong Bao Tran Nguyen - 5th Johor Open 2018, Round 4.14 | ChessEver

Broadcasts Rankings Desktop News Account Get the App

0–1

Truong Bao Tran Nguyen

1873

1

--:--

abcdefgh

87654321

2119

0

--:--

King's Indian, fianchetto without c4· A49

1.

2.

3.

4.

5.

6.

7.

8.

9.

10.

11.

12.

13.

14.

15.

16.

17.

18.

19.

20.

21.

22.

23.

0–1

Engine

5th Johor Open 2018

Round 4.14 · Dec 12, 2018 · 0-1 · TC Classical

A49 · King's Indian, fianchetto without c4

2119FIDE 5207410

Truong Bao Tran Nguyen

1873FIDE 12402311

Get the full experience

Live games, notifications and analysis.

Download on the