C. Linford vs Mi Sandu - 4NCL 2008-9, Round 5 | ChessEver

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½–½

MS

Mi Sandu

2285

½

--:--

abcdefgh

87654321

CL

C. Linford

2119

½

--:--

· B81

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½–½

Engine

4NCL 2008-9

Round 5 · Jan 17, 2009 · Draw · TC Classical

B81

White

C. Linford

2119

Black

Mi Sandu

2285

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