Howard Zhong vs Christopher Yang - 2nd Ivy League Challenge, Round 1.2 | ChessEver

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½–½

Christopher Yang

2145

½

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abcdefgh

87654321

2024

½

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Nimzo-Indian, 4.e3· E40

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½–½

Engine

2nd Ivy League Challenge

Round 1.2 · Nov 8, 2019 · Draw · TC Classical

E40 · Nimzo-Indian, 4.e3

2024FIDE 2077043

Christopher Yang

2145FIDE 2073404

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