Haroldas Vainauskas vs Algirdas Rauduve - TCh-LTU 2019, Round 6.10 | ChessEver

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½–½

Algirdas Rauduve

1643

½

--:--

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Haroldas Vainauskas

1393

½

--:--

Nimzo-Indian, Leningrad variation· E30

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½–½

Engine

TCh-LTU 2019

Round 6.10 · Apr 27, 2019 · Draw · TC Classical

E30 · Nimzo-Indian, Leningrad variation

Haroldas Vainauskas

1393FIDE 12817104

Algirdas Rauduve

1643FIDE 12808440

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