Rohan Shan Tze Navaratnam vs WFM C De Seroux - 1st Tal Mem IM 2019, Round 3.4 | ChessEver

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1–0

2151

0

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87654321

Rohan Shan Tze Navaratnam

2068

1

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Sicilian, Alapin's variation (2.c3)· B22

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1–0

Engine

1st Tal Mem IM 2019

Round 3.4 · May 1, 2019 · 1-0 · TC Classical

B22 · Sicilian, Alapin's variation (2.c3)

Rohan Shan Tze Navaratnam

2068MASFIDE 5727413

WFM C De Seroux

2151SUIFIDE 1305620

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